2-2(n-3)3n=21+7

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Solution for 2-2(n-3)3n=21+7 equation: 



2-2(n-3)3n=21+7

We move all terms to the left:

2-2(n-3)3n-(21+7)=0

We add all the numbers together, and all the variables

-2(n-3)3n+2-28=0

We add all the numbers together, and all the variables

-2(n-3)3n-26=0

We multiply parentheses

-6n^2+18n-26=0

a = -6; b = 18; c = -26;
Δ = b2-4ac
Δ = 182-4·(-6)·(-26)
Δ = -300
Delta is less than zero, so there is no solution for the equation

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