2-2/5b=3

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Solution for 2-2/5b=3 equation: 



2-2/5b=3

We move all terms to the left:

2-2/5b-(3)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We add all the numbers together, and all the variables

-2/5b-1=0

We multiply all the terms by the denominator


-1*5b-2=0

Wy multiply elements

-5b-2=0

We move all terms containing b to the left, all other terms to the right

-5b=2

b=2/-5

b=-2/5

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