2-27x2=0

Solution for 2-27x2=0 equation:

2-27x^2=0

a = -27; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-27)·2
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{6}}{2*-27}=\frac{0-6\sqrt{6}}{-54}
=-\frac{6\sqrt{6}}{-54}
=-\frac{\sqrt{6}}{-9}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{6}}{2*-27}=\frac{0+6\sqrt{6}}{-54}
=\frac{6\sqrt{6}}{-54}
=\frac{\sqrt{6}}{-9}
$