2-2k=-8-5(k-2)

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Solution for 2-2k=-8-5(k-2) equation: 



2-2k=-8-5(k-2)

We move all terms to the left:

2-2k-(-8-5(k-2))=0



We calculate terms in parentheses: -(-8-5(k-2)), so:

-8-5(k-2)

determiningTheFunctionDomain
-5(k-2)-8

We multiply parentheses

-5k+10-8

We add all the numbers together, and all the variables

-5k+2

Back to the equation:

-(-5k+2)



We get rid of parentheses

-2k+5k-2+2=0

We add all the numbers together, and all the variables

3k=0

k=0/3

k=0

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