2-2s=(3/4)s+13

Solution for 2-2s=(3/4)s+13 equation:

2-2s=(3/4)s+13

We move all terms to the left:

2-2s-((3/4)s+13)=0


Domain of the equation: 4)s+13)!=0

s!=0/1

s!=0

s∈R


We add all the numbers together, and all the variables

-2s-((+3/4)s+13)+2=0

We multiply all the terms by the denominator


-2s*4)s+13)-((+2*4)s+13)+3=0

We add all the numbers together, and all the variables

-2s*4)s+13)-(8s+13)+3=0

Wy multiply elements

-8s^2=0

a = -8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-8)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$s=\frac{-b}{2a}=\frac{0}{-16}=0$