2-2s=2/4s+13

Solution for 2-2s=2/4s+13 equation:

2-2s=2/4s+13

We move all terms to the left:

2-2s-(2/4s+13)=0


Domain of the equation: 4s+13)!=0

s∈R


We get rid of parentheses

-2s-2/4s-13+2=0

We multiply all the terms by the denominator


-2s*4s-13*4s+2*4s-2=0

Wy multiply elements

-8s^2-52s+8s-2=0

We add all the numbers together, and all the variables

-8s^2-44s-2=0

a = -8; b = -44; c = -2;
Δ = b2-4ac
Δ = -442-4·(-8)·(-2)
Δ = 1872
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1872}=\sqrt{144*13}=\sqrt{144}*\sqrt{13}=12\sqrt{13}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-12\sqrt{13}}{2*-8}=\frac{44-12\sqrt{13}}{-16}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+12\sqrt{13}}{2*-8}=\frac{44+12\sqrt{13}}{-16}
$