2-3(2+6c)=4(c+1)-8

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Solution for 2-3(2+6c)=4(c+1)-8 equation:


Simplifying
2 + -3(2 + 6c) = 4(c + 1) + -8
2 + (2 * -3 + 6c * -3) = 4(c + 1) + -8
2 + (-6 + -18c) = 4(c + 1) + -8

Combine like terms: 2 + -6 = -4
-4 + -18c = 4(c + 1) + -8

Reorder the terms:
-4 + -18c = 4(1 + c) + -8
-4 + -18c = (1 * 4 + c * 4) + -8
-4 + -18c = (4 + 4c) + -8

Reorder the terms:
-4 + -18c = 4 + -8 + 4c

Combine like terms: 4 + -8 = -4
-4 + -18c = -4 + 4c

Add '4' to each side of the equation.
-4 + 4 + -18c = -4 + 4 + 4c

Combine like terms: -4 + 4 = 0
0 + -18c = -4 + 4 + 4c
-18c = -4 + 4 + 4c

Combine like terms: -4 + 4 = 0
-18c = 0 + 4c
-18c = 4c

Solving
-18c = 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-18c + -4c = 4c + -4c

Combine like terms: -18c + -4c = -22c
-22c = 4c + -4c

Combine like terms: 4c + -4c = 0
-22c = 0

Divide each side by '-22'.
c = 0

Simplifying
c = 0

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