2-3(2+6z)=4(z+1)+18

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Solution for 2-3(2+6z)=4(z+1)+18 equation:


Simplifying
2 + -3(2 + 6z) = 4(z + 1) + 18
2 + (2 * -3 + 6z * -3) = 4(z + 1) + 18
2 + (-6 + -18z) = 4(z + 1) + 18

Combine like terms: 2 + -6 = -4
-4 + -18z = 4(z + 1) + 18

Reorder the terms:
-4 + -18z = 4(1 + z) + 18
-4 + -18z = (1 * 4 + z * 4) + 18
-4 + -18z = (4 + 4z) + 18

Reorder the terms:
-4 + -18z = 4 + 18 + 4z

Combine like terms: 4 + 18 = 22
-4 + -18z = 22 + 4z

Solving
-4 + -18z = 22 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-4 + -18z + -4z = 22 + 4z + -4z

Combine like terms: -18z + -4z = -22z
-4 + -22z = 22 + 4z + -4z

Combine like terms: 4z + -4z = 0
-4 + -22z = 22 + 0
-4 + -22z = 22

Add '4' to each side of the equation.
-4 + 4 + -22z = 22 + 4

Combine like terms: -4 + 4 = 0
0 + -22z = 22 + 4
-22z = 22 + 4

Combine like terms: 22 + 4 = 26
-22z = 26

Divide each side by '-22'.
z = -1.181818182

Simplifying
z = -1.181818182

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