2-3(2x-1)=3x-(x+2)

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Solution for 2-3(2x-1)=3x-(x+2) equation: 



2-3(2x-1)=3x-(x+2)

We move all terms to the left:

2-3(2x-1)-(3x-(x+2))=0

We multiply parentheses

-6x-(3x-(x+2))+3+2=0



We calculate terms in parentheses: -(3x-(x+2)), so:

3x-(x+2)

We get rid of parentheses

3x-x-2

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

-6x-(2x-2)+5=0

We get rid of parentheses

-6x-2x+2+5=0

We add all the numbers together, and all the variables

-8x+7=0

We move all terms containing x to the left, all other terms to the right

-8x=-7

x=-7/-8

x=7/8

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