2-3(4-x)=5(2-x)+48

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Solution for 2-3(4-x)=5(2-x)+48 equation: 



2-3(4-x)=5(2-x)+48

We move all terms to the left:

2-3(4-x)-(5(2-x)+48)=0

We add all the numbers together, and all the variables

-3(-1x+4)-(5(-1x+2)+48)+2=0

We multiply parentheses

3x-(5(-1x+2)+48)-12+2=0



We calculate terms in parentheses: -(5(-1x+2)+48), so:

5(-1x+2)+48

We multiply parentheses

-5x+10+48

We add all the numbers together, and all the variables

-5x+58

Back to the equation:

-(-5x+58)



We add all the numbers together, and all the variables

3x-(-5x+58)-10=0

We get rid of parentheses

3x+5x-58-10=0

We add all the numbers together, and all the variables

8x-68=0

We move all terms containing x to the left, all other terms to the right

8x=68

x=68/8

x=8+1/2

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