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2-3(4-x)=5(2-x)+x
We move all terms to the left:
2-3(4-x)-(5(2-x)+x)=0
We add all the numbers together, and all the variables
-3(-1x+4)-(5(-1x+2)+x)+2=0
We multiply parentheses
3x-(5(-1x+2)+x)-12+2=0
We calculate terms in parentheses: -(5(-1x+2)+x), so:We add all the numbers together, and all the variables
5(-1x+2)+x
We add all the numbers together, and all the variables
x+5(-1x+2)
We multiply parentheses
x-5x+10
We add all the numbers together, and all the variables
-4x+10
Back to the equation:
-(-4x+10)
3x-(-4x+10)-10=0
We get rid of parentheses
3x+4x-10-10=0
We add all the numbers together, and all the variables
7x-20=0
We move all terms containing x to the left, all other terms to the right
7x=20
x=20/7
x=2+6/7
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