2-3(4-x)=6(x+3)-4x

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Solution for 2-3(4-x)=6(x+3)-4x equation: 



2-3(4-x)=6(x+3)-4x

We move all terms to the left:

2-3(4-x)-(6(x+3)-4x)=0

We add all the numbers together, and all the variables

-3(-1x+4)-(6(x+3)-4x)+2=0

We multiply parentheses

3x-(6(x+3)-4x)-12+2=0



We calculate terms in parentheses: -(6(x+3)-4x), so:

6(x+3)-4x

We add all the numbers together, and all the variables

-4x+6(x+3)

We multiply parentheses

-4x+6x+18

We add all the numbers together, and all the variables

2x+18

Back to the equation:

-(2x+18)



We add all the numbers together, and all the variables

3x-(2x+18)-10=0

We get rid of parentheses

3x-2x-18-10=0

We add all the numbers together, and all the variables

x-28=0

We move all terms containing x to the left, all other terms to the right

x=28

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