2-3(4a-2)=3(2a-6)-4/5a

Solution for 2-3(4a-2)=3(2a-6)-4/5a equation:

2-3(4a-2)=3(2a-6)-4/5a

We move all terms to the left:

2-3(4a-2)-(3(2a-6)-4/5a)=0


Domain of the equation: 5a)!=0

a!=0/1

a!=0

a∈R


We multiply parentheses

-12a-(3(2a-6)-4/5a)+6+2=0

We multiply all the terms by the denominator


-12a*5a)-(3(2a-6)+6*5a)+2*5a)-4=0

Wy multiply elements

-60a^2+150a^2=0

We add all the numbers together, and all the variables

90a^2=0

a = 90; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·90·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{180}=0$