2-3(5x+4)-(6+2x)=12-4(2+x)

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Solution for 2-3(5x+4)-(6+2x)=12-4(2+x) equation: 



2-3(5x+4)-(6+2x)=12-4(2+x)

We move all terms to the left:

2-3(5x+4)-(6+2x)-(12-4(2+x))=0

We add all the numbers together, and all the variables

-3(5x+4)-(2x+6)-(12-4(x+2))+2=0

We multiply parentheses

-15x-(2x+6)-(12-4(x+2))-12+2=0

We get rid of parentheses

-15x-2x-(12-4(x+2))-6-12+2=0



We calculate terms in parentheses: -(12-4(x+2)), so:

12-4(x+2)

determiningTheFunctionDomain
-4(x+2)+12

We multiply parentheses

-4x-8+12

We add all the numbers together, and all the variables

-4x+4

Back to the equation:

-(-4x+4)



We add all the numbers together, and all the variables

-17x-(-4x+4)-16=0

We get rid of parentheses

-17x+4x-4-16=0

We add all the numbers together, and all the variables

-13x-20=0

We move all terms containing x to the left, all other terms to the right

-13x=20

x=20/-13

x=-1+7/13

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