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2-3(5x-5)=9x+(2-x)
We move all terms to the left:
2-3(5x-5)-(9x+(2-x))=0
We add all the numbers together, and all the variables
-3(5x-5)-(9x+(-1x+2))+2=0
We multiply parentheses
-15x-(9x+(-1x+2))+15+2=0
We calculate terms in parentheses: -(9x+(-1x+2)), so:We add all the numbers together, and all the variables
9x+(-1x+2)
We get rid of parentheses
9x-1x+2
We add all the numbers together, and all the variables
8x+2
Back to the equation:
-(8x+2)
-15x-(8x+2)+17=0
We get rid of parentheses
-15x-8x-2+17=0
We add all the numbers together, and all the variables
-23x+15=0
We move all terms containing x to the left, all other terms to the right
-23x=-15
x=-15/-23
x=15/23
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