2-3(b+5)=-3b-13

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Solution for 2-3(b+5)=-3b-13 equation:


Simplifying
2 + -3(b + 5) = -3b + -13

Reorder the terms:
2 + -3(5 + b) = -3b + -13
2 + (5 * -3 + b * -3) = -3b + -13
2 + (-15 + -3b) = -3b + -13

Combine like terms: 2 + -15 = -13
-13 + -3b = -3b + -13

Reorder the terms:
-13 + -3b = -13 + -3b

Add '13' to each side of the equation.
-13 + 13 + -3b = -13 + 13 + -3b

Combine like terms: -13 + 13 = 0
0 + -3b = -13 + 13 + -3b
-3b = -13 + 13 + -3b

Combine like terms: -13 + 13 = 0
-3b = 0 + -3b
-3b = -3b

Add '3b' to each side of the equation.
-3b + 3b = -3b + 3b

Combine like terms: -3b + 3b = 0
0 = -3b + 3b

Combine like terms: -3b + 3b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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