2-3(x+1)+7(x-5)=0

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Solution for 2-3(x+1)+7(x-5)=0 equation: 


Simplifying
2 + -3(x + 1) + 7(x + -5) = 0

Reorder the terms:
2 + -3(1 + x) + 7(x + -5) = 0
2 + (1 * -3 + x * -3) + 7(x + -5) = 0
2 + (-3 + -3x) + 7(x + -5) = 0

Reorder the terms:
2 + -3 + -3x + 7(-5 + x) = 0
2 + -3 + -3x + (-5 * 7 + x * 7) = 0
2 + -3 + -3x + (-35 + 7x) = 0

Reorder the terms:
2 + -3 + -35 + -3x + 7x = 0

Combine like terms: 2 + -3 = -1
-1 + -35 + -3x + 7x = 0

Combine like terms: -1 + -35 = -36
-36 + -3x + 7x = 0

Combine like terms: -3x + 7x = 4x
-36 + 4x = 0

Solving
-36 + 4x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '36' to each side of the equation.
-36 + 36 + 4x = 0 + 36

Combine like terms: -36 + 36 = 0
0 + 4x = 0 + 36
4x = 0 + 36

Combine like terms: 0 + 36 = 36
4x = 36

Divide each side by '4'.
x = 9

Simplifying
x = 9

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