2-3(x+4)=9-(3+2x)-18

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Solution for 2-3(x+4)=9-(3+2x)-18 equation: 



2-3(x+4)=9-(3+2x)-18

We move all terms to the left:

2-3(x+4)-(9-(3+2x)-18)=0

We add all the numbers together, and all the variables

-3(x+4)-(9-(2x+3)-18)+2=0

We multiply parentheses

-3x-(9-(2x+3)-18)-12+2=0



We calculate terms in parentheses: -(9-(2x+3)-18), so:

9-(2x+3)-18

determiningTheFunctionDomain
-(2x+3)+9-18

We add all the numbers together, and all the variables

-(2x+3)-9

We get rid of parentheses

-2x-3-9

We add all the numbers together, and all the variables

-2x-12

Back to the equation:

-(-2x-12)



We add all the numbers together, and all the variables

-3x-(-2x-12)-10=0

We get rid of parentheses

-3x+2x+12-10=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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