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2-3(x+5)=7x-(10x+13)
We move all terms to the left:
2-3(x+5)-(7x-(10x+13))=0
We multiply parentheses
-3x-(7x-(10x+13))-15+2=0
We calculate terms in parentheses: -(7x-(10x+13)), so:We add all the numbers together, and all the variables
7x-(10x+13)
We get rid of parentheses
7x-10x-13
We add all the numbers together, and all the variables
-3x-13
Back to the equation:
-(-3x-13)
-3x-(-3x-13)-13=0
We get rid of parentheses
-3x+3x+13-13=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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