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2-3(x+5)=9-(3+2x)
We move all terms to the left:
2-3(x+5)-(9-(3+2x))=0
We add all the numbers together, and all the variables
-3(x+5)-(9-(2x+3))+2=0
We multiply parentheses
-3x-(9-(2x+3))-15+2=0
We calculate terms in parentheses: -(9-(2x+3)), so:We add all the numbers together, and all the variables
9-(2x+3)
determiningTheFunctionDomain -(2x+3)+9
We get rid of parentheses
-2x-3+9
We add all the numbers together, and all the variables
-2x+6
Back to the equation:
-(-2x+6)
-3x-(-2x+6)-13=0
We get rid of parentheses
-3x+2x-6-13=0
We add all the numbers together, and all the variables
-1x-19=0
We move all terms containing x to the left, all other terms to the right
-x=19
x=19/-1
x=-19
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