2-3(x-2(-4(x+1)+3x-2)+3)=x-5

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Solution for 2-3(x-2(-4(x+1)+3x-2)+3)=x-5 equation: 



2-3(x-2(-4(x+1)+3x-2)+3)=x-5

We move all terms to the left:

2-3(x-2(-4(x+1)+3x-2)+3)-(x-5)=0

We get rid of parentheses

-3(x-2(-4(x+1)+3x-2)+3)-x+5+2=0

We add all the numbers together, and all the variables

-1x-3(x-2(-4(x+1)+3x-2)+3)+7=0

We move all terms containing x to the left, all other terms to the right

-1x-3(x-2(-4(x+1)+3x-2)+3)=-7

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