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2-3(x-4)=5(2-x)+4x
We move all terms to the left:
2-3(x-4)-(5(2-x)+4x)=0
We add all the numbers together, and all the variables
-3(x-4)-(5(-1x+2)+4x)+2=0
We multiply parentheses
-3x-(5(-1x+2)+4x)+12+2=0
We calculate terms in parentheses: -(5(-1x+2)+4x), so:We add all the numbers together, and all the variables
5(-1x+2)+4x
We add all the numbers together, and all the variables
4x+5(-1x+2)
We multiply parentheses
4x-5x+10
We add all the numbers together, and all the variables
-1x+10
Back to the equation:
-(-1x+10)
-3x-(-1x+10)+14=0
We get rid of parentheses
-3x+1x-10+14=0
We add all the numbers together, and all the variables
-2x+4=0
We move all terms containing x to the left, all other terms to the right
-2x=-4
x=-4/-2
x=+2
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