2-3(y-1)=5y+(y-4)

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Solution for 2-3(y-1)=5y+(y-4) equation:



2-3(y-1)=5y+(y-4)
We move all terms to the left:
2-3(y-1)-(5y+(y-4))=0
We multiply parentheses
-3y-(5y+(y-4))+3+2=0
We calculate terms in parentheses: -(5y+(y-4)), so:
5y+(y-4)
We get rid of parentheses
5y+y-4
We add all the numbers together, and all the variables
6y-4
Back to the equation:
-(6y-4)
We add all the numbers together, and all the variables
-3y-(6y-4)+5=0
We get rid of parentheses
-3y-6y+4+5=0
We add all the numbers together, and all the variables
-9y+9=0
We move all terms containing y to the left, all other terms to the right
-9y=-9
y=-9/-9
y=1

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