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2-3x(x-5)=5
We move all terms to the left:
2-3x(x-5)-(5)=0
We add all the numbers together, and all the variables
-3x(x-5)-3=0
We multiply parentheses
-3x^2+15x-3=0
a = -3; b = 15; c = -3;
Δ = b2-4ac
Δ = 152-4·(-3)·(-3)
Δ = 189
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{189}=\sqrt{9*21}=\sqrt{9}*\sqrt{21}=3\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3\sqrt{21}}{2*-3}=\frac{-15-3\sqrt{21}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3\sqrt{21}}{2*-3}=\frac{-15+3\sqrt{21}}{-6} $
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