2-3z=7(6z)+12

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Solution for 2-3z=7(6z)+12 equation: 



2-3z=7(6z)+12

We move all terms to the left:

2-3z-(7(6z)+12)=0

We get rid of parentheses

-3z-76z-12+2=0

We add all the numbers together, and all the variables

-79z-10=0

We move all terms containing z to the left, all other terms to the right

-79z=10

z=10/-79

z=-10/79

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