2-4(3k+3)+6k=k

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Solution for 2-4(3k+3)+6k=k equation: 



2-4(3k+3)+6k=k

We move all terms to the left:

2-4(3k+3)+6k-(k)=0

We add all the numbers together, and all the variables

5k-4(3k+3)+2=0

We multiply parentheses

5k-12k-12+2=0

We add all the numbers together, and all the variables

-7k-10=0

We move all terms containing k to the left, all other terms to the right

-7k=10

k=10/-7

k=-1+3/7

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