2-4(z+1)=3z-(2+z)

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Solution for 2-4(z+1)=3z-(2+z) equation:


Simplifying
2 + -4(z + 1) = 3z + -1(2 + z)

Reorder the terms:
2 + -4(1 + z) = 3z + -1(2 + z)
2 + (1 * -4 + z * -4) = 3z + -1(2 + z)
2 + (-4 + -4z) = 3z + -1(2 + z)

Combine like terms: 2 + -4 = -2
-2 + -4z = 3z + -1(2 + z)
-2 + -4z = 3z + (2 * -1 + z * -1)
-2 + -4z = 3z + (-2 + -1z)

Reorder the terms:
-2 + -4z = -2 + 3z + -1z

Combine like terms: 3z + -1z = 2z
-2 + -4z = -2 + 2z

Add '2' to each side of the equation.
-2 + 2 + -4z = -2 + 2 + 2z

Combine like terms: -2 + 2 = 0
0 + -4z = -2 + 2 + 2z
-4z = -2 + 2 + 2z

Combine like terms: -2 + 2 = 0
-4z = 0 + 2z
-4z = 2z

Solving
-4z = 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-4z + -2z = 2z + -2z

Combine like terms: -4z + -2z = -6z
-6z = 2z + -2z

Combine like terms: 2z + -2z = 0
-6z = 0

Divide each side by '-6'.
z = 0

Simplifying
z = 0

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