2-5(-4b+5)=3(2b-3)

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Solution for 2-5(-4b+5)=3(2b-3) equation: 



2-5(-4b+5)=3(2b-3)

We move all terms to the left:

2-5(-4b+5)-(3(2b-3))=0

We multiply parentheses

20b-(3(2b-3))-25+2=0



We calculate terms in parentheses: -(3(2b-3)), so:

3(2b-3)

We multiply parentheses

6b-9

Back to the equation:

-(6b-9)



We add all the numbers together, and all the variables

20b-(6b-9)-23=0

We get rid of parentheses

20b-6b+9-23=0

We add all the numbers together, and all the variables

14b-14=0

We move all terms containing b to the left, all other terms to the right

14b=14

b=14/14

b=1

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