2-5(25b-40)=1-4(16b+8)

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Solution for 2-5(25b-40)=1-4(16b+8) equation: 



2-5(25b-40)=1-4(16b+8)

We move all terms to the left:

2-5(25b-40)-(1-4(16b+8))=0

We multiply parentheses

-125b-(1-4(16b+8))+200+2=0



We calculate terms in parentheses: -(1-4(16b+8)), so:

1-4(16b+8)

determiningTheFunctionDomain
-4(16b+8)+1

We multiply parentheses

-64b-32+1

We add all the numbers together, and all the variables

-64b-31

Back to the equation:

-(-64b-31)



We add all the numbers together, and all the variables

-125b-(-64b-31)+202=0

We get rid of parentheses

-125b+64b+31+202=0

We add all the numbers together, and all the variables

-61b+233=0

We move all terms containing b to the left, all other terms to the right

-61b=-233

b=-233/-61

b=3+50/61

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