2-5(3x-4)=5(6+x)

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Solution for 2-5(3x-4)=5(6+x) equation: 



2-5(3x-4)=5(6+x)

We move all terms to the left:

2-5(3x-4)-(5(6+x))=0

We add all the numbers together, and all the variables

-5(3x-4)-(5(x+6))+2=0

We multiply parentheses

-15x-(5(x+6))+20+2=0



We calculate terms in parentheses: -(5(x+6)), so:

5(x+6)

We multiply parentheses

5x+30

Back to the equation:

-(5x+30)



We add all the numbers together, and all the variables

-15x-(5x+30)+22=0

We get rid of parentheses

-15x-5x-30+22=0

We add all the numbers together, and all the variables

-20x-8=0

We move all terms containing x to the left, all other terms to the right

-20x=8

x=8/-20

x=-2/5

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