2-5(3y-2)=4(1-3y)

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Solution for 2-5(3y-2)=4(1-3y) equation: 



2-5(3y-2)=4(1-3y)

We move all terms to the left:

2-5(3y-2)-(4(1-3y))=0

We add all the numbers together, and all the variables

-5(3y-2)-(4(-3y+1))+2=0

We multiply parentheses

-15y-(4(-3y+1))+10+2=0



We calculate terms in parentheses: -(4(-3y+1)), so:

4(-3y+1)

We multiply parentheses

-12y+4

Back to the equation:

-(-12y+4)



We add all the numbers together, and all the variables

-15y-(-12y+4)+12=0

We get rid of parentheses

-15y+12y-4+12=0

We add all the numbers together, and all the variables

-3y+8=0

We move all terms containing y to the left, all other terms to the right

-3y=-8

y=-8/-3

y=2+2/3

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