2-5(x-2)=3(-x+1)

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Solution for 2-5(x-2)=3(-x+1) equation: 



2-5(x-2)=3(-x+1)

We move all terms to the left:

2-5(x-2)-(3(-x+1))=0

We add all the numbers together, and all the variables

-5(x-2)-(3(-1x+1))+2=0

We multiply parentheses

-5x-(3(-1x+1))+10+2=0



We calculate terms in parentheses: -(3(-1x+1)), so:

3(-1x+1)

We multiply parentheses

-3x+3

Back to the equation:

-(-3x+3)



We add all the numbers together, and all the variables

-5x-(-3x+3)+12=0

We get rid of parentheses

-5x+3x-3+12=0

We add all the numbers together, and all the variables

-2x+9=0

We move all terms containing x to the left, all other terms to the right

-2x=-9

x=-9/-2

x=4+1/2

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