2-5/6x+1/10x-4/5=0

Solution for 2-5/6x+1/10x-4/5=0 equation:

2-5/6x+1/10x-4/5=0


Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R


We calculate fractions


(-240x^2)/1500x^2+(-1250x)/1500x^2+150x/1500x^2+2=0

We multiply all the terms by the denominator


(-240x^2)+(-1250x)+150x+2*1500x^2=0

We add all the numbers together, and all the variables

(-240x^2)+150x+(-1250x)+2*1500x^2=0

Wy multiply elements

(-240x^2)+3000x^2+150x+(-1250x)=0

We get rid of parentheses

-240x^2+3000x^2+150x-1250x=0

We add all the numbers together, and all the variables

2760x^2-1100x=0

a = 2760; b = -1100; c = 0;
Δ = b2-4ac
Δ = -11002-4·2760·0
Δ = 1210000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1210000}=1100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1100)-1100}{2*2760}=\frac{0}{5520}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1100)+1100}{2*2760}=\frac{2200}{5520}
=55/138
$