2-5c=6+10(4-3c)

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Solution for 2-5c=6+10(4-3c) equation: 



2-5c=6+10(4-3c)

We move all terms to the left:

2-5c-(6+10(4-3c))=0

We add all the numbers together, and all the variables

-5c-(6+10(-3c+4))+2=0



We calculate terms in parentheses: -(6+10(-3c+4)), so:

6+10(-3c+4)

determiningTheFunctionDomain
10(-3c+4)+6

We multiply parentheses

-30c+40+6

We add all the numbers together, and all the variables

-30c+46

Back to the equation:

-(-30c+46)



We get rid of parentheses

-5c+30c-46+2=0

We add all the numbers together, and all the variables

25c-44=0

We move all terms containing c to the left, all other terms to the right

25c=44

c=44/25

c=1+19/25

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