2-5i/4i

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Solution for 2-5i/4i equation: 


i in (-oo:+oo)

2-(((5*i)/4)*i) = 0

(-5/4)*i^2+2 = 0

-5/4*i^2 = -2 // : -5/4

i^2 = 8/5

i^2 = 8/5 // ^ 1/2

abs(i) = (8/5)^(1/2)

i = (8/5)^(1/2) or i = -(8/5)^(1/2)

i in { (8/5)^(1/2), -(8/5)^(1/2) }

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