2-5i/6i

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Solution for 2-5i/6i equation: 


i in (-oo:+oo)

2-(((5*i)/6)*i) = 0

(-5/6)*i^2+2 = 0

-5/6*i^2 = -2 // : -5/6

i^2 = 12/5

i^2 = 12/5 // ^ 1/2

abs(i) = (12/5)^(1/2)

i = (12/5)^(1/2) or i = -(12/5)^(1/2)

i in { (12/5)^(1/2), -(12/5)^(1/2) }

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