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2-5x=((6x-5)/3)
We move all terms to the left:
2-5x-(((6x-5)/3))=0
We multiply all the terms by the denominator
-5x*3))-(((6x-5)+2*3))=0
We add all the numbers together, and all the variables
-5x*3))-(((6x-5)=0
Wy multiply elements
-15x^2=0
a = -15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-15)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-30}=0$
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