2-5x=(-(6x-5)/(3))

Solution for 2-5x=(-(6x-5)/(3)) equation:

2-5x=(-(6x-5)/(3))

We move all terms to the left:

2-5x-((-(6x-5)/(3)))=0

We multiply all the terms by the denominator


-5x*3))-((-(6x-5)+2*3))=0

We add all the numbers together, and all the variables

-5x*3))-((-(6x-5)=0

Wy multiply elements

-15x^2-(6x-5)=0

We get rid of parentheses

-15x^2-6x+5=0

a = -15; b = -6; c = +5;
Δ = b2-4ac
Δ = -62-4·(-15)·5
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{21}}{2*-15}=\frac{6-4\sqrt{21}}{-30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{21}}{2*-15}=\frac{6+4\sqrt{21}}{-30}
$