2-6(z+1)=4(z-2)+10

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Solution for 2-6(z+1)=4(z-2)+10 equation:


Simplifying
2 + -6(z + 1) = 4(z + -2) + 10

Reorder the terms:
2 + -6(1 + z) = 4(z + -2) + 10
2 + (1 * -6 + z * -6) = 4(z + -2) + 10
2 + (-6 + -6z) = 4(z + -2) + 10

Combine like terms: 2 + -6 = -4
-4 + -6z = 4(z + -2) + 10

Reorder the terms:
-4 + -6z = 4(-2 + z) + 10
-4 + -6z = (-2 * 4 + z * 4) + 10
-4 + -6z = (-8 + 4z) + 10

Reorder the terms:
-4 + -6z = -8 + 10 + 4z

Combine like terms: -8 + 10 = 2
-4 + -6z = 2 + 4z

Solving
-4 + -6z = 2 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-4 + -6z + -4z = 2 + 4z + -4z

Combine like terms: -6z + -4z = -10z
-4 + -10z = 2 + 4z + -4z

Combine like terms: 4z + -4z = 0
-4 + -10z = 2 + 0
-4 + -10z = 2

Add '4' to each side of the equation.
-4 + 4 + -10z = 2 + 4

Combine like terms: -4 + 4 = 0
0 + -10z = 2 + 4
-10z = 2 + 4

Combine like terms: 2 + 4 = 6
-10z = 6

Divide each side by '-10'.
z = -0.6

Simplifying
z = -0.6

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