2-8(m-4)=-6(m+6)+8m

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Solution for 2-8(m-4)=-6(m+6)+8m equation: 



2-8(m-4)=-6(m+6)+8m

We move all terms to the left:

2-8(m-4)-(-6(m+6)+8m)=0

We multiply parentheses

-8m-(-6(m+6)+8m)+32+2=0



We calculate terms in parentheses: -(-6(m+6)+8m), so:

-6(m+6)+8m

We add all the numbers together, and all the variables

8m-6(m+6)

We multiply parentheses

8m-6m-36

We add all the numbers together, and all the variables

2m-36

Back to the equation:

-(2m-36)



We add all the numbers together, and all the variables

-8m-(2m-36)+34=0

We get rid of parentheses

-8m-2m+36+34=0

We add all the numbers together, and all the variables

-10m+70=0

We move all terms containing m to the left, all other terms to the right

-10m=-70

m=-70/-10

m=+7

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