2-x(2+x)=4x+11+x(2-x)

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Solution for 2-x(2+x)=4x+11+x(2-x) equation: 



2-x(2+x)=4x+11+x(2-x)

We move all terms to the left:

2-x(2+x)-(4x+11+x(2-x))=0

We add all the numbers together, and all the variables

-x(x+2)-(4x+11+x(-1x+2))+2=0

We multiply parentheses

-x^2-2x-(4x+11+x(-1x+2))+2=0



We calculate terms in parentheses: -(4x+11+x(-1x+2)), so:

4x+11+x(-1x+2)

determiningTheFunctionDomain
4x+x(-1x+2)+11

We multiply parentheses

-1x^2+4x+2x+11

We add all the numbers together, and all the variables

-1x^2+6x+11

Back to the equation:

-(-1x^2+6x+11)



We add all the numbers together, and all the variables

-1x^2-(-1x^2+6x+11)-2x+2=0

We get rid of parentheses

-1x^2+1x^2-6x-2x-11+2=0

We add all the numbers together, and all the variables

-8x-9=0

We move all terms containing x to the left, all other terms to the right

-8x=9

x=9/-8

x=-1+1/8

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