2-x+2=4(1/2x)-2

Solution for 2-x+2=4(1/2x)-2 equation:

2-x+2=4(1/2x)-2

We move all terms to the left:

2-x+2-(4(1/2x)-2)=0


Domain of the equation: 2x)-2)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-x-(4(+1/2x)-2)+2+2=0

We add all the numbers together, and all the variables

-1x-(4(+1/2x)-2)+4=0

We multiply all the terms by the denominator


-1x*2x)-2)-(4(+4*2x)-2)+1=0

Wy multiply elements

-2x^2+8x=0

a = -2; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-2)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-2}=\frac{-16}{-4}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-2}=\frac{0}{-4}
=0
$