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2.1k(2k-4.7)-8.19=0
We multiply parentheses
4k^2-9.4k-8.19=0
a = 4; b = -9.4; c = -8.19;
Δ = b2-4ac
Δ = -9.42-4·4·(-8.19)
Δ = 219.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.4)-\sqrt{219.4}}{2*4}=\frac{9.4-\sqrt{219.4}}{8} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.4)+\sqrt{219.4}}{2*4}=\frac{9.4+\sqrt{219.4}}{8} $
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