2.2c-3=2(6-c)+7c

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Solution for 2.2c-3=2(6-c)+7c equation:



2.2c-3=2(6-c)+7c
We move all terms to the left:
2.2c-3-(2(6-c)+7c)=0
We add all the numbers together, and all the variables
2.2c-(2(-1c+6)+7c)-3=0
We calculate terms in parentheses: -(2(-1c+6)+7c), so:
2(-1c+6)+7c
We add all the numbers together, and all the variables
7c+2(-1c+6)
We multiply parentheses
7c-2c+12
We add all the numbers together, and all the variables
5c+12
Back to the equation:
-(5c+12)
We get rid of parentheses
2.2c-5c-12-3=0
We add all the numbers together, and all the variables
-2.8c-15=0
We move all terms containing c to the left, all other terms to the right
-2.8c=15
c=15/-2.8
c=-5+1/2.8

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