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2.2x^2-7x+3=0
a = 2.2; b = -7; c = +3;
Δ = b2-4ac
Δ = -72-4·2.2·3
Δ = 22.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{22.6}}{2*2.2}=\frac{7-\sqrt{22.6}}{4.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{22.6}}{2*2.2}=\frac{7+\sqrt{22.6}}{4.4} $
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