2.4=3m(1m+4)

Solution for 2.4=3m(1m+4) equation:

2.4=3m(1m+4)

We move all terms to the left:

2.4-(3m(1m+4))=0

We add all the numbers together, and all the variables

-(3m(m+4))+2.4=0


We calculate terms in parentheses: -(3m(m+4)), so:

3m(m+4)

We multiply parentheses

3m^2+12m

Back to the equation:

-(3m^2+12m)


We get rid of parentheses

-3m^2-12m+2.4=0

a = -3; b = -12; c = +2.4;
Δ = b2-4ac
Δ = -122-4·(-3)·2.4
Δ = 172.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{172.8}}{2*-3}=\frac{12-\sqrt{172.8}}{-6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{172.8}}{2*-3}=\frac{12+\sqrt{172.8}}{-6}
$