2.5(y-2)/2+y=1.2(y+3)/3

Solution for 2.5(y-2)/2+y=1.2(y+3)/3 equation:

2.5(y-2)/2+y=1.2(y+3)/3

We move all terms to the left:

2.5(y-2)/2+y-(1.2(y+3)/3)=0

We add all the numbers together, and all the variables

y+2.5(y-2)/2-(1.2(y+3)/3)=0

We calculate fractions


y+(2.5y)/()+(-(1.2(y+3)*2)/()=0


We calculate terms in parentheses: +(-(1.2(y+3)*2)/(), so:

-(1.2(y+3)*2)/(

We multiply all the terms by the denominator


-(1.2(y+3)*2)


We calculate terms in parentheses: -(1.2(y+3)*2), so:

1.2(y+3)*2

We multiply parentheses

2.4y+7.2

Back to the equation:

-(2.4y+7.2)


We get rid of parentheses

-2.4y-7.2

Back to the equation:

+(-2.4y-7.2)


We add all the numbers together, and all the variables

y+(+2.5y)/()+(-2.4y-7.2)=0

We get rid of parentheses

y+(+2.5y)/()-2.4y-7.2=0

We multiply all the terms by the denominator


y*()+(+2.5y)-(2.4y)*()-(7.2)*()=0

We add all the numbers together, and all the variables

y*()+(+2.5y)-(+2.4y)*()-(7.2)*()=0

We add all the numbers together, and all the variables

y*()+(+2.5y)-(+2.4y)*()=0

We get rid of parentheses

y*()+2.5y-(+2.4y)*()=0

We add all the numbers together, and all the variables

2.5y+y*()-(+2.4y)*()=0