2.5x2+20x+40=0

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Solution for 2.5x2+20x+40=0 equation: 



2.5x^2+20x+40=0

a = 2.5; b = 20; c = +40;
Δ = b2-4ac
Δ = 202-4·2.5·40
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-20}{5}=-4$

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