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2.5x^2+3.25x-16.5=0
a = 2.5; b = 3.25; c = -16.5;
Δ = b2-4ac
Δ = 3.252-4·2.5·(-16.5)
Δ = 175.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.25)-\sqrt{175.5625}}{2*2.5}=\frac{-3.25-\sqrt{175.5625}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.25)+\sqrt{175.5625}}{2*2.5}=\frac{-3.25+\sqrt{175.5625}}{5} $
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