2.6+3n=4/5n+12

Solution for 2.6+3n=4/5n+12 equation:

2.6+3n=4/5n+12

We move all terms to the left:

2.6+3n-(4/5n+12)=0


Domain of the equation: 5n+12)!=0

n∈R


We get rid of parentheses

3n-4/5n-12+2.6=0

We multiply all the terms by the denominator


3n*5n-12*5n+(2.6)*5n-4=0

We multiply parentheses

3n*5n-12*5n+13n-4=0

Wy multiply elements

15n^2-60n+13n-4=0

We add all the numbers together, and all the variables

15n^2-47n-4=0

a = 15; b = -47; c = -4;
Δ = b2-4ac
Δ = -472-4·15·(-4)
Δ = 2449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-\sqrt{2449}}{2*15}=\frac{47-\sqrt{2449}}{30}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+\sqrt{2449}}{2*15}=\frac{47+\sqrt{2449}}{30}
$